SOLUTION: I'm having some trouble graphing this function for my online homework. Here it is: 2x^2- 3x- 7 I used to quadratic equation to find the zeros: x= [3- sqrt:(65)]/ 4 (-

Algebra ->  Rational-functions -> SOLUTION: I'm having some trouble graphing this function for my online homework. Here it is: 2x^2- 3x- 7 I used to quadratic equation to find the zeros: x= [3- sqrt:(65)]/ 4 (-      Log On


   

Question 360875: I'm having some trouble graphing this function for my online homework.
Here it is:
2x^2- 3x- 7
I used to quadratic equation to find the zeros:
x= [3- sqrt:(65)]/ 4 (-1.26..., 0)
x= [3+ sqrt:(65)]/ 4 (2.76..., 0)
The minimum point was found to be at (3/4, -65/8)
I tried graphing the minimum point and one of the zero points and my answer is wrong. Any help?
Thanks SO much! :]
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=2x%5E2-3x-7
Complete the square to put it into vertex form,
f%28x%29=2%28x%5E2-%283%2F2%29x%29-7
f%28x%29=2%28x%5E2-%283%2F2%29x%2B9%2F16%29-7-2%289%2F16%29
f%28x%29=2%28x-3%2F4%29%5E2-56%2F8-9%2F8
f%28x%29=2%28x-3%2F4%29%5E2-65%2F8
The vertex is (3%2F4,-65%2F8).
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