SOLUTION: One race car travels at 200 miles per hour and has a 30 minute head start. The second race car travels at 763 milers per hour. At what distance with the faster car catch the slow
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Question 360785: One race car travels at 200 miles per hour and has a 30 minute head start. The second race car travels at 763 milers per hour. At what distance with the faster car catch the slower car? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! One race car travels at 200 miles per hour and has a 30 minute head start.
The second race car travels at 763 milers per hour.
At what distance with the faster car catch the slower car?
:
Wow, 763 mph, isn't that about the speed of sound, anyway
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Let t = time required for it to catch the slower car
then
(t + .5) - travel time of the slower car
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When this happens the two cars will have traveled the same distance
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Write a dist equation, dist = speed * time
:
763t = 200(t+.5)
763t = 200t + 100
763t - 200t = 100
563t = 100
t =
t = .1776 hrs
:
Find the dist:
.1776*763 = 135.5 miles, the faster car catches the slower car.
:
confirm this using the slower car
200(.1776+.5) = 135.5 mi also
