SOLUTION: solve: log(6x)-log(x+1)=log4

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Question 36073: solve: log(6x)-log(x+1)=log4
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Recall that:log%28M%29-log%28N%29+=+log%28M%2FN%29 and if log%28A%29+=+log%28B%29 then A+=+B Applying these ideas to your problem:
log%28%286x%29%29-log%28%28x%2B1%29%29+=+log%28%284%29%29
log%28%28%286x%29%2F%28x%2B1%29%29%29+=+log%28%284%29%29
%28%286x%29%2F%28x%2B1%29%29+=+4 Multiply both sides by (x+1)
6x+=+4%28x%2B1%29 Simplify.
6x+=+4x%2B4 Subtract 4x from both sides.
2x+=+4 Finally, divide both sides by 2.
x+=+2