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(1) 4x - 4y - z = 38
(2) x + 4y - 3z = 6
(3) -3x + 2y - z = -14
Pick any one of the three equations and pick one of the variables in it to solve for.
I'll pick equation (2) and pick x to solve for:
(2) x + 4y - 3z = 6
(4) x = 6 - 4y + 3z
Now substitute 6 - 4y + 3z for x in the other two equations:
Substituting 6 - 4y + 3z for x in equation (1) and simplifying:
(1) 4x - 4y - z = 38
4(6 - 4y + 3z) - 4y - z = 38
24 - 16y + 12z - 4y - z = 38
24 - 20y + 11z = 38
(5) -20y + 11z = 14
Substituting 6 - 4y + 3z for x in equation (3) and simplifying:
(3) -3x + 2y - z = -14
(1) -3x + 2y - z = -14
-3(6 - 4y + 3z) + 2y - z = -14
-18 + 12y - 9z + 2y - z = -14
-18 + 14y - 10z = -14
(6) 14y - 10z = 4
Now we put equations (5) and (6) together as a system of two
equations and 2 variables:
(5) -20y + 11z = 14
(6) 14y - 10z = 4
It's too hard to do that by substitution, so I'll use elimination:
To eliminate z, multiply equation (5) through by 10, and equation (6)
through by 11, and add the resulting equations term by term:
-200y + 110z = 140
154y - 110z = 44
------------------
-46y = 184
(7) y = -4
Substituting in equation (6)
(6) 14y - 10z = 4
14(-4) - 10z = 4
-56 - 10z = 4
-10z = 60
(8) z = -6
Now we substitute for y amd z from equations (7) and (8) into equation (4)
(4) x = 6 - 4y + 3z
x = 6 - 4(-4) + 3(-6)
x = 6 + 16 - 18
x = 4
Edwin
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