Question 360566: 1. logx 8=3
2.log 10(2x-4) _ log 10(x+2) =1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1. logx 8=3
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x^3 = 8
x = 2
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2.log 10(2x-4) - log 10(x+2) =1
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log10[(2x-4)/(x+2)] = 1
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[(2x-4)/(x+2)] = 10
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2x-4 = 10x+20
8x = -24
x = -3
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But x cannot be -3 in the original equation
because you cannot have the log of a negative
number.
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No solution:
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Cheers,
stan H.
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