Question 360475: The perimeter of a rectangle is 52 inches. The length is 4 less than twice its width. Find the dimensions of the rectangle Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle is 52 inches. The length is 4 less than twice its width. Find the dimensions of the rectangle
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let width be w
length = 2w-4
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P= 2*(l+W)
P=2*(w+2w-4)
P=2*(3w-4)
P=6w-8
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6w-8=52
6w=62+8
6w=60
/6
w= 10 in. the width
length = 2w-4 = 20-4=16 in.
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m.ananth@hotmail.ca
