SOLUTION: Hello, if you could help me with a problem I would be ever so grateful! I do not know where to start on this one. I have reviewed my notes but cannot seem to figure it out.
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-> SOLUTION: Hello, if you could help me with a problem I would be ever so grateful! I do not know where to start on this one. I have reviewed my notes but cannot seem to figure it out.
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Question 360454: Hello, if you could help me with a problem I would be ever so grateful! I do not know where to start on this one. I have reviewed my notes but cannot seem to figure it out.
Write an equation of the line containing a given point and perpendicular to the given line.
(6,7); 4x + y =5
Thank you for any assistance you can give. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Write an equation of the line containing a given point and perpendicular to the given line.
(6,7); 4x + y = 5
:
Find the slope of the given equation by putting it in the slope intercept form
4x + y = 5
y = -4x + 5
slope (m1) = -4
:
The relationship of the slopes of perpendicular lines is m1*m2 = -1
We know m1, find m2
-4*m2 = -1
Divide both sides by -4
m2 = +, this is slope of the equation we are looking for
:
Use the point/slope form here: y - y1 = m(x-x1)
Given: x1=6, y1=7
y - 7 = (x - 6)
y - 7 = x -
y = x - + 7
y = x - +
y = x +
let's just call it
y = x + 5.5; is the equation (green) and passes thru 6.7
:
:
We can see this on a graph
