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Question 360280: find an equation of the line containing the given pair of points.
(1/4,-1/2) and (3/4, 3 )
what is the equation of the line
y=
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! First, determine slope of:
(1/4,-1/2) and (3/4, 3 )
.
m = (y2-y1)/(x2-x1)
m = (3-(-1/2))/((3/4)-(1/4))
m = (3+1/2)/(3/4-1/4)
m = (6/2+1/2)/(3/4-1/4)
m = (5/2)/(2/4)
m = (5/2)/(1/2)
m = 5
.
Now, take the slope (5) and use one of the two points (3/4, 3 ) and plug it into the "point-slope" form:
y - y1 = m(x - x1)
y - 3 = 5(x - 3/4)
y - 3 = 5x - 15/4
y = 5x - 15/4 + 3
y = 5x - 15/4 + 12/4
y = 5x - 3/4 (this is what they're looking for)
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