SOLUTION: A rectangular garden is to be surrounded by a walkway of constant width. The garden’s dimensions are 20 ft by 28 ft. The total area, garden plus walkway, is to be 1,100 ft2. What m

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Question 360167: A rectangular garden is to be surrounded by a walkway of constant width. The garden’s dimensions are 20 ft by 28 ft. The total area, garden plus walkway, is to be 1,100 ft2. What must be the width of the walkway?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
(20+2X)(28+2X)=1,100
560+56X+40X+4X^2=1,100
4X^2+96X+560-1,100=0
4X^2+96X-540=0
4(X^2+24X-135)=0
X+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(-24+-SQRT[2462-4*1*-135])/2*1
X=(-24+-SQRT[576+540])/2
X=(-24+-SQRT1,116)/2
X=(-24+-33.4)/2
X=(-24+33.4)/2
X=9.4/2
X=4.7 FT. IS THE WIDTH OF THE WALKWAY.