Question 360059: find three consecutive natural numbers such that the sum of the first and the second is 39 more than the third number. Found 2 solutions by vleith, mananth:Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! Let the smallest number be x.
Then the next two natural numbers are x+1 and x +2
You are told
So the numbers are 40, 41 a nd 42.
Check your answer, Is 40+41 = 42+39??
You can put this solution on YOUR website! find three consecutive natural numbers such that the sum of the first and the second is 39 more than the third number.
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x,x+1,x+2
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x+x+1=x+2+39
2x+1=x+41
2x-x=41-1
x=40
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40,41,42
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m.ananth@hotmail.ca
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