SOLUTION: Hello, I have a math question that is: Find 3 consecutive odd integers such that the first is 23 less than the sum of the second and third. i have tried 23x-(x+2)+(x+4)= (x+2)

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Hello, I have a math question that is: Find 3 consecutive odd integers such that the first is 23 less than the sum of the second and third. i have tried 23x-(x+2)+(x+4)= (x+2)      Log On


   

Question 359810: Hello, I have a math question that is: Find 3 consecutive odd integers such that the first is 23 less than the sum of the second and third.
i have tried 23x-(x+2)+(x+4)= (x+2) + (x+4). As i found out this does not give me the right answer. I'm not really sure how to set up this problem. If you could please help me that would be nice.
Thank you for your time.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
"Find 3 consecutive odd integers such that the first is 23 less than the sum of the second and third" means that x=%28x%2B2%29%2B%28x%2B4%29-23


x=%28x%2B2%29%2B%28x%2B4%29-23 Start with the given equation.


x=2x-17 Combine like terms on the right side.


x-2x=-17 Subtract 2x from both sides.


-x=-17 Combine like terms on the left side.


x=%28-17%29%2F%28-1%29 Divide both sides by -1 to isolate x.


x=17 Reduce.


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Answer:

So the solution is x=17


This means that the 3 numbers are: 17, 19, 21


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim