Question 359802: Hello, in my algebra riddle book, I found a problem that does not show the answer in the back of the textbook.
I need help approaching this problem, The farthest I went was assigning variables to the things I needed to find.
Since it is an algebra problem, would I need to setup an equation of sorts for each thing I am trying to find?
I was not able to find similar problems on the internet.
Problem:
In a tub of Halloween candy, all but 16 are Snickers, all but 16 are Milky Ways, and but 16 are Plain M & M’s, and all but 18 are Peanut M & M’s. How many of each type of candy bars are in the tub?
Help would be much appreciated.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In a tub of Halloween candy, all but 16 are Snickers, all but 16 are Milky Ways, and but 16 are Plain M & M’s, and all but 18 are Peanut M & M’s. How many of each type of candy bars are in the tub?
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Total number of bars is S+MW+PMM+pMM
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Equations:
0 + MW + PMM + pMM = 16
S + 0 + PMM + pMM = 16
S + MW + 0 + pMM = 16
S + MM + PMM + 0 = 18
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I used a matrix function on a TI-84 and got
Snickers = 6
Milky Way = 6
Plain MM = 6
Peanut MM = 4
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Cheers,
Stan H.
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