SOLUTION: 17-(4k-2) >= 2(k+3) -68k-34 >= 2k+3 -68k-2k >= 37 -70k >= 37 k >= 37/70 ??????

Algebra ->  Inequalities -> SOLUTION: 17-(4k-2) >= 2(k+3) -68k-34 >= 2k+3 -68k-2k >= 37 -70k >= 37 k >= 37/70 ??????      Log On


   

Question 359795: 17-(4k-2) >= 2(k+3)
-68k-34 >= 2k+3
-68k-2k >= 37
-70k >= 37
k >= 37/70
??????
Answer by Jk22(389) About Me  (Show Source):
You can put this solution on YOUR website!
17-(4k-2) >= 2(k+3) | distributivity : a*(b+c)=a*b + a*c

17 - 4k + 2 >= 2k + 6

19 - 4k >= 2k + 6

19 - 6 >= 2k + 4k

13 >= 6k

k <= 13/6