SOLUTION: Amber has five dollars in her purse consistent of nickels, dimes and quarters. If she has one more quarter then dimes, and one less nickel then dimes, how many of each type of coin

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Amber has five dollars in her purse consistent of nickels, dimes and quarters. If she has one more quarter then dimes, and one less nickel then dimes, how many of each type of coin      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 35971: Amber has five dollars in her purse consistent of nickels, dimes and quarters. If she has one more quarter then dimes, and one less nickel then dimes, how many of each type of coin does she have
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
Amber has five dollars in her purse consistent of nickels(N SAY) , dimes ( D SAY )and quarters (Q SAY ) . If she has one more quarter then dimes,
D+1=Q.............I
and one less nickel then dimes,
D-1=N...................II
how many of each type of coin does she have
TOTAL IS 5 $=500 CENTS
25Q+10D+5N=500......................
5Q+2D+N=100...........................III.......SUBSTITUTING FROM EQN.I AND EQN.II
5(D+1)+2D+D-1=100
5D+5+2D+D-1=100
8D=100-5+1=96
D=96/8=12
HENC
D=12................12*10=120 CENTS
N=12-1=11............11*5= 55 CENTS
Q=12+1=13...........13*25=325 CENTS
TOTAL.....................500 CENTS = 5 $