SOLUTION: Jim and John drive from point A to point B in separate cars. Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm. Assume both men drive at constant spe
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Jim and John drive from point A to point B in separate cars. Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm. Assume both men drive at constant spe
Log On
Question 359546: Jim and John drive from point A to point B in separate cars. Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm. Assume both men drive at constant speeds. Find when John catches up with Jim Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Jim and John drive from point A to point B in separate cars.
Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm.
Assume both men drive at constant speeds.
Find when John catches up with Jim.
:
Let d = distance from A to B
Jim's travel time: 10 hrs (6am to 4pm)
Jon's travel time: 5 hrs (10am to 4pm
:
Let t = Jon's travel time when he catches Jim
Then
(t+4) = Jim's travel time when this happens (Jim leave 4 hrs earlier)
and we know = Jim's speed
and = Jon's speed
:
When Jon catches Jim, they will have traveled the same distance; Dist = speed * time. (t+4) = *t
multiply both sides by 10 to get rid of the denominators, results
d(t+4) = 2dt
divide both sides by d
t + 4 = 2t
4 = 2t - t
t = 4 hrs, Jon's travel time
then
4 + 4 = 8 hrs; Jim's travel time
:
10 am + 4 hrs = 2 pm when Jon overtakes Jim
:
