Question 359390: I was just wondering if someone could double check my work on this problem:
A box contains 8 good parts and 4 defective parts. If a sample of 2 parts is drawn from the box at random (without replacement), what is the probability of each of the following:
Two good parts are selected. (my answer 8/12 * 7/11 = 14/33 or 42%)
Two defective parts are selected. (my answer 4/12 * 3/11= 1/11 or 9%)
One good part is selected first, and then one defective part is selected second?
(my answer 8/12 or 66% chance of good part first, 4/11 or 36% chance of defective part being chosen second 8/12 * 4/11 = 8/33 or 24% totalling a 24% chance)
Exactly one defective part out of the two is selected. (my answer ?)
Any input would be apprieciated!
Answer by Fombitz(32388) (Show Source):
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