Question 359293: what is the height of a triangle, where the area is 56 inches squared and a base of 14 inches?
Answer by geforcewong(2)   (Show Source):
You can put this solution on YOUR website! The Area of a triangle is one-half the base times the height of the triangle.
So A=(1/2)bh, where A= Area, b = base, h = height.
Since you are given the Area (A =56 inches^2)
and you are given the base (b = 14 inches),
You can find the height (h) by plugging the given Area and base into the equation:
A = (1/2)bh
So,
Plug in A= 56 inches^2 and b = 14 inches:
56 inches^2 = (1/2)(14 inches)h
Simplified:
56 inches^2 = (7 inches)h
Dividing both sides by 7 inches:
56 inches^2 / 7 inches = h
Simplifying units of measurement (inches^2 divided by inches = inches):
h = (56/7) inches
Simplified:
h = 8 inches
Check your work: A = (1/2)(14)(8) = (7)(8) = 56 = Area that was given.
Therefore, when the area of a triangle is 56 inches squared and has a base of 14 inches, the height will be 8 inches.
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