SOLUTION: how would yu solv a quadratic equation for x^2-4x+6=0 and for x^2+1=0

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Question 358802: how would yu solv a quadratic equation for x^2-4x+6=0 and for x^2+1=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use the quadratic formula,
x%5E2-4x%2B6=0
a=1
b=-4
c=6
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x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%284+%2B-+sqrt%28+%28-4%29%5E2-4%2A1%2A6+%29%29%2F%282%2A1%29+
x+=+%284+%2B-+sqrt%28+16-24%29%29%2F2+
x+=+%284+%2B-+sqrt%28+-8%29%29%2F2+
x+=+%284+%2B-+2sqrt%28+-2%29%29%2F2+
highlight%28x+=+2+%2B-+sqrt%28+2%29i+%29 where i=sqrt%28-1%29
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Now follow the same procedure for the second equation.