SOLUTION: solve Linear sestems when w=1 w+2x+2y+z=-2 w+3x-2y-z=-6 -2w-x+3y+3z=6 w+4x+y+2z=-14 think you

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Question 358679: solve Linear sestems when w=1
w+2x+2y+z=-2
w+3x-2y-z=-6
-2w-x+3y+3z=6
w+4x+y+2z=-14
think you
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
[A]=matrix%284%2C4%2C1%2C2%2C2%2C1%2C1%2C3%2C-2%2C-1%2C-2%2C-1%2C3%2C3%2C1%2C4%2C1%2C2%29%29
[x]=%28matrix%284%2C1%2Cw%2Cx%2Cy%2Cz%29%29
[b]=%28matrix%284%2C1%2C-2%2C-6%2C6%2C14%29%29
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[A][x]=[b]
[x]=[A]inv[b]
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det[A]=1%2F18
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[A]inv=
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[x]=%28matrix%284%2C1%2C-9%2C2%2C19%2F3%2C-29%2F3%29%29
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Not sure what you mean by "when w=1" because then you'd have 4 equations with 3 unknowns.