SOLUTION: solve x^2-16x+32=0 by completing the square

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Question 35866: solve x^2-16x+32=0 by completing the square
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
x^2-16x+32=0

First add -32 to each side and leave a blank space after the x^2- 16x .
x%5E2+-+16x+%2B+______=+-32+%2B+_____

You must take half of the -16 (which is -4) and square it (which would be 16). Add +16 to each side of the equation on the blank spaces I provided you.
x%5E2+-+16x+%2B+16=+-32+%2B+16

Now, notice that the left side is a perfect square trinomial:
%28x-4%29%5E2+=+-16

Now you can take the square root of each side:
x-4+=+0+%2B-+sqrt%28-16%29

Remember that sqrt%28-16%29+=+4i??
x-4+=+0+%2B-+4i%29

Last add +4 to each side:
x+=+4+%2B-+4i+

R^2 at SCC