SOLUTION: Suppose the amount of time it takes a popcorn kernel to pop is normally distributed with a mean of 150 seconds and a standard deviation of 15 seconds. If a popcorn kernal is rando

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Question 358602: Suppose the amount of time it takes a popcorn kernel to pop is normally distributed with a mean of 150 seconds and a standard deviation of 15 seconds. If a popcorn kernal is randomly selected, what is the probability that it takes between 130 seconds to 170 seconds for the kernal to pop?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use the z-score.
z=%28x-mu%29%2Fsigma
z%5B1%5D=%28130-150%29%2F15
z%5B2%5D=%28170-150%29%2F15
Then find P%28z%5B1%5D%29 and P%28z%5B2%5D%29.
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P%28130%3Cx%3C170%29=P%28z%5B2%5D%29-P%28z%5B1%5D%29