SOLUTION: A cattle train left Miami and traveled toward New York. 14 hours later a diesel train left traveling at 45 km/h in an effort to catch up to the cattle train. After traveling for fo
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Question 358588: A cattle train left Miami and traveled toward New York. 14 hours later a diesel train left traveling at 45 km/h in an effort to catch up to the cattle train. After traveling for four hours the diesel train finally caught up. What was the cattle trains average speed? Found 2 solutions by jrfrunner, ankor@dixie-net.com:Answer by jrfrunner(365) (Show Source):
You can put this solution on YOUR website! distance = rate * time or rate=distance/time or time=distance/rate
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The deisel train catches up to the cattle train. That means they travel the same distance at that instance.
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The distance travelled by the deisel train: d=r*t=45mph*4hours=180 miles
It also means that the cattle train travel 180 miles when they were together.
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But the cattle train had travelled for an additional 14 hours or a total of 14+4 =18 hours
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Cattle rate (or speed)=d/t=180miles/18hours=10mph
You can put this solution on YOUR website! A cattle train left Miami and traveled toward New York.
14 hours later a diesel train left traveling at 45 km/h in an effort to catch up to the cattle train.
After traveling for four hours the diesel train finally caught up.
What was the cattle trains average speed?
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Let s = cattle train speed
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The cattle train will be traveling 14 + 4 = 18hrs when the diesel catches up
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When the diesel overtakes the cattle, they will have traveled the same distance
Write a distance equation; dist = speed * time
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Cattle dist = diesel dist
18s = 4*45
18s = 180
s = 10 kmh is the cattle train
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Both travel 180 km
