SOLUTION: Solve the nonlinear system: 2x^2+y^2= 6 x^2-4y^2= -15

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Question 35853: Solve the nonlinear system:
2x^2+y^2= 6
x^2-4y^2= -15
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
2X~2+Y~2=6 X~2-4Y~2=-15 THEN X~2=4Y~2-15 AND SUBSTITUTING 4Y~2-15 FOR X~2
IN THE FIRST EQUTION WE GET 2(4Y~2-15)+Y~2=6 OR 8Y~2-30+Y~2=6 OR
9Y~2=36 OR Y~2=4 OR Y=2 NOW REPLACINF Y WITH 2 IN THW SECOND EQUATION WE GET
X~2-4*2~2=-15 OR X~2-16=-15 OR X~2=1 OR X=1
PROOF 2(1)~2+2~2=6 OR 2+4=6 OR 6=6 & 1-4*2~2=-15 OR 1-16=-15 OR -15=-15