SOLUTION: How do you solve the system equation? 6a+ 2b= 11 3a= 8b+ 1

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Question 358296: How do you solve the system equation?
6a+ 2b= 11
3a= 8b+ 1
Found 2 solutions by mananth, ewatrrr:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
6a+ 2b= 11
3a= 8b+ 1
re write this equation.
3a-8b=1
multiply by -2 and it to first equation to eliminate x
-6a+16b=-2
add
6a-6a+2b+16b=11-2
18b=9
divide by 9
2b=1
/2
b = 1/2
..
plug value of b in second equation
3a=4+1
3a=5
divide by 3
a= 5/3
...
m.ananth@hotmail.ca

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Adding the two equations in the system together & solving by eliminating one of the variables

6a+ 2b= 11 

3a= 8b+ 1

arranging in like form

6a + 2b= 11 

3a - 8b= 1



Multiplying first equation thru by 4

24a + 8b= 44 

3a  - 8b = 1



adding the two equation together (eliminating b variable)

27a = 45

a = 45/27 = 5/3

Solving for the b  substituting a = 5/3  

3a  = 8b +1

5  = 8b + 1

4 = 8b

1/2 = b

checkiing the answer using one of the equation

24(5/3) + 8*(1/2) = 40 + 4 = 44