SOLUTION: x^4-16=0

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Question 35827: x^4-16=0
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
This equation factors as the difference of two squares:
x%5E4+-+16=0+
%28x%5E2+-+4%29%28x%5E2+%2B+4%29+=0

The first factor factors again:
%28x-2%29%28x%2B2%29%28x%5E2+%2B+4%29+=+0

Now, set each factor equal to zero and solve:
x=2 or x=+-2 or x%5E2=-4
x=2 or x=+-2 or x+=+sqrt%28-4%29 or +x+=+-+sqrt%28-4%29+
x=2 or x=+-2 or x=+2i or x=+-2i+


R^2 at SCC