Question 357518: How many liters of water must be added to 50 L of a 30% acid solution in order to produce a 20% acid solution? Answer by ewatrrr(24785) (Show Source):
Hi,
Let x be the water added
.30*50 = .20(50 L +x)
simplify and Solve
.30*50 - .20*50 L = .20x
.10*50L = .20x
25L = x
25 liters of water would need to be added
checking our answer
15 = .20(75)