SOLUTION: factor completley p2+2pq-24q2

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Question 357489: factor completley p2+2pq-24q2
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at p%5E2%2B2pq-24q%5E2 we can see that the first term is p%5E2 and the last term is -24q%5E2 where the coefficients are 1 and -24 respectively.

Now multiply the first coefficient 1 and the last coefficient -24 to get -24. Now what two numbers multiply to -24 and add to the middle coefficient 2? Let's list all of the factors of -24:



Factors of -24:
1,2,3,4,6,8,12,24

-1,-2,-3,-4,-6,-8,-12,-24 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -24
(1)*(-24)
(2)*(-12)
(3)*(-8)
(4)*(-6)
(-1)*(24)
(-2)*(12)
(-3)*(8)
(-4)*(6)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to 2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 2

First NumberSecond NumberSum
1-241+(-24)=-23
2-122+(-12)=-10
3-83+(-8)=-5
4-64+(-6)=-2
-124-1+24=23
-212-2+12=10
-38-3+8=5
-46-4+6=2



From this list we can see that -4 and 6 add up to 2 and multiply to -24


Now looking at the expression p%5E2%2B2pq-24q%5E2, replace 2pq with -4pq%2B6pq (notice -4pq%2B6pq adds up to 2pq. So it is equivalent to 2pq)

p%5E2%2Bhighlight%28-4pq%2B6pq%29%2B-24q%5E2


Now let's factor p%5E2-4pq%2B6pq-24q%5E2 by grouping:


%28p%5E2-4pq%29%2B%286pq-24q%5E2%29 Group like terms


p%28p-4q%29%2B6q%28p-4q%29 Factor out the GCF of p out of the first group. Factor out the GCF of 6q out of the second group


%28p%2B6q%29%28p-4q%29 Since we have a common term of p-4q, we can combine like terms

So p%5E2-4pq%2B6pq-24q%5E2 factors to %28p%2B6q%29%28p-4q%29


So this also means that p%5E2%2B2pq-24q%5E2 factors to %28p%2B6q%29%28p-4q%29 (since p%5E2%2B2pq-24q%5E2 is equivalent to p%5E2-4pq%2B6pq-24q%5E2)



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Answer:
So p%5E2%2B2pq-24q%5E2 factors to %28p%2B6q%29%28p-4q%29