SOLUTION: one grade of tes, worth $3.20 per pound, is to be mixed with another grade worth $2.00 per pound to make 20 pounds that will sell for $2.72 per pound. how many pounds of the $3.20

Algebra ->  Percentages: Solvers, Trainers, Word Problems and pie charts -> SOLUTION: one grade of tes, worth $3.20 per pound, is to be mixed with another grade worth $2.00 per pound to make 20 pounds that will sell for $2.72 per pound. how many pounds of the $3.20      Log On


   

Question 357317: one grade of tes, worth $3.20 per pound, is to be mixed with another grade worth $2.00 per pound to make 20 pounds that will sell for $2.72 per pound. how many pounds of the $3.20 tea must be used? and how many pounds of the $2.00 tea must be used?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Let x be the amount of the $3.20/lb grade.  Then (20-x) would be the amount of the $2.00/lb tea.

$3.20*x + $2.00(20 - x) = $2.72*20lb

simplify and Solve

$3.20*x + $2.00*20 - 2.00x =$2.72*20lb

$1.20*x  = $2.72*20lb - $2.00*20

$1.20*x  = .72*20lb = 14.4

x = 12lb

the amount of the $2.00 tea would be 8 lb

check your answer

3.20*12  + 2.00*8 = 38.4 + 16 = 2.72*20 = 54.40