Question 357199: Find an equation of the line that passes through the points 4,4 and 8,-2
Found 3 solutions by Alan3354, mananth, neatmath:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Given 2 points example.
Find the equation of the line thru the points (2,1) and (3,5)
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This is a 2 step process. First find the slope of the line thru the points.
slope, m = diffy/diffx
m = (5-1)/(3-2)
m = 4
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Now use y = mx + b with either point to find b, the y-intercept.
y = mx + b
5 = 4*3 + b
b = -7
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y = mx + b
y = 4x - 7 is the answer.
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Another approach using determinants:
|x y 1|
|2 1 1| = 0
|3 5 1|
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x(1-5) - y(2-3) + 1(10-3) = 0
-4x + y + 7 = 0
y = 4x - 7
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For further assistance, or to check your work, email me via the thank you note
or at Moral Loophole@aol.com
Answer by mananth(16946)  (Show Source):
You can put this solution on YOUR website! 4,4 and 8,-2
slope = y2-y1/x2-x1
slope = -6/4 = -3/2
...
y=mx+b
plug values of xy & m
4=-3/2*4+b
4=-6+b
b=10
...
the equation
y = -3x/2 +10
...
m.ananth@hotmail.ca
Answer by neatmath(302)  (Show Source):
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