SOLUTION: a person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. how many of each coin does the person have?

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Question 357157: a person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. how many of each coin does the person have?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=Q+7
.25Q+.10D=2.80
.25Q+.10(Q+7)=2.80
.25Q+10Q+.70=2.80
.35Q=2.80-.70
.35Q=2.10
Q=2.10/.35
Q=6 QUARTERS.
D=6+7=13 DIMES.
PROOF:
.25*6+.10*13=2.80
1.50+1.30=2.80
2.80=2.80