SOLUTION: The sum of the first and last of four consecutive odd intergers is 48, what are the four intergers?

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Question 356873: The sum of the first and last of four consecutive odd intergers is 48, what are the four intergers?
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi,
*Note: consecutive odd intergers differ by 2
Let n represeent the first then (n+2), (n+4) and (n+6) would be the other three
question states
n + (n + 6) = 48
2n = 42
n = 21
four consecutive odd intergers would be 21, 23, 25, 27
check your answer
21+ 27 = 48