Question 35677: the trapezoid has an area of 48cm squared. find the value of x the height is x+1 base is x+6 and base is x Answer by narayaba(40) (Show Source):
You can put this solution on YOUR website! area of trapeaoid is (1/2)*height*(base1 + base2)
height = x+1
base1= x+6
base2 =x
area = (1/2)*(x+1)*(x+x+6) but area is given to be 48
therefor (1/2)(x+1)(2x+6) = 48
(x+1)(x+6)=48
x^2+6x+6=48
x^2+6x+6-48=0
x^2+6x-42=0
x=(-6+sqrt(36+168))/(2) or x =(+6+sqrt(36+168))/(2)
x = (-6+14.28)/2 or x=(+6+14.28)/2
x = -4.14 or 10.14
length of side cannot be negative therefore x = 10.14
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