SOLUTION: how many liters of a 40% alcohol solution must be mixed with 65% solution to obtain 20 liters of a 50% solution?

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Question 356697: how many liters of a 40% alcohol solution must be mixed with 65% solution to obtain 20 liters of a 50% solution?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
0.40x+%2B+0.65%2820-x%29+=+20%2A0.50,
0.40x+%2B+13-0.65x+=+10,
-0.25x+=+-3,
x+=+12, # liters 40% alcohol solution, and 20 - 12 = 8 liters 65% alcohol solution.