SOLUTION: Fred walks 3 miles an hour. John walks 2 miles an hour. If they live 4 miles apart, and leave their house at the same time, when will they meet?
Question 356612: Fred walks 3 miles an hour. John walks 2 miles an hour. If they live 4 miles apart, and leave their house at the same time, when will they meet? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Fred walks 3 miles an hour. John walks 2 miles an hour. If they live 4 miles apart, and leave their house at the same time, when will they meet?
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fred = 3mph
john = 2mph
they walk towards each other
so their effective speed = 3+2 = 5mph
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distance = 4 miles
time = distance / speed
4/5 hours
=48 minutes
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m.ananth@hotmail.ca
