SOLUTION: Find the vertex and focus of the Parabola whose equation is 4(y-2) = (x-4) ^2. Thank you for your help!

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Question 35661: Find the vertex and focus of the Parabola whose equation is 4(y-2) = (x-4) ^2.
Thank you for your help!
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
4(y-2) = (x-4) ^2
(y-2) = (1/4)(x-4)^2
y=(1/4)(x-4)^2+2
In y=a(x-h)^2+k the vertex is (h,k), so the vertex for this equation is (4,2)
The length from vertex to focus is: p=(1/4a)=(1/1)=1, so the focu is (4,3)