SOLUTION: at the beginning of a bicycle ride for charity, roberto and juana are 30 miles apart. If they Leave at the same time and ride in the same direction, roberto overtakes juana in 6 ho
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Question 356607: at the beginning of a bicycle ride for charity, roberto and juana are 30 miles apart. If they Leave at the same time and ride in the same direction, roberto overtakes juana in 6 hours. if they ride toward each other, they meet in 1 hour. what are their speeds? Found 2 solutions by robertb, mananth:Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! Let r = speed of roberto, j = speed of juana. Using the formula D = RT, (distance = rate x time), the 1st and 2nd sentences give . The 3rd sentence implies that .
The first equation is the same as , after transposition and dividing both sides by 6. The 2nd equation is just . Adding corresponding sides of these 2 equations, we get , or r = 17.5 miles per hour. Then j=30 - r = 12.5 miles per hour.
You can put this solution on YOUR website! at the beginning of a bicycle ride for charity, roberto and juana are 30 miles apart. If they Leave at the same time and ride in the same direction, roberto overtakes juana in 6 hours. if they ride toward each other, they meet in 1 hour. what are their speeds?
let robreto's speed =x
juana's speed =y : x>y
distance = 30 miles apart
...
roberto catches up x=y mph
distance = speed * time
30=(x-y)*6
/6
x-y =5.....................1
...
when they ride toward the speed is x+ymph
distance = 30
distance = speed * time
30=1*(x+y)
x+y=30....................2
add 1 & 2
2x=35
/2
x= 35/2
= 17.5 mph robert's speed
...
x-y = 5
17.5-y=5
y=17.5-5
y=12.5 mph Juana's speed
...
m.ananth@hotmail.ca
