SOLUTION: In testing a hybrid engine, engineers are trying various mixtures of gasoline and methanol. How much of a 90% gasoline mixture and a 75% gasoline mixture would be needed for 600 L

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Question 356576: In testing a hybrid engine, engineers are trying various mixtures of gasoline and methanol. How much of a 90% gasoline mixture and a 75% gasoline mixture would be needed for 600 L of an 85% gasoline mixture?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 90% mixture, B the amount of 75% mixture.
Volume:
1.A%2BB=600
Concentration:
90A%2B75B=85%28600%29
2.18A%2B15B=10200
Multiply eq. 1 by (-15) and add to eq. 2 to eliminate B and solve for A.
-15A-15B%2B18A%2B15B=-9000%2B10200
3A=1200
highlight%28A=400%29ml
Then from eq. 1,
400%2BB=600
highlight%28B=200%29ml