SOLUTION: Find an equation for the linear function satisfying the condition that the graph of its inverse function is perpendicular to the line 4x+ 2y-3 passing through the point (-1,1)

Hi,



question states its inverse function is perpendicular to 2x +2y - 3 = 0

4x +2y - 3 = 0

y = -2x + 3/2  slope m = -2

standard slope intercept form of an equation of a line is

y= mx + b

two lines with slopes that are negative reciprocals of each other are perpendicular to each other

inverse function would have a slope m = (1/2)

y = (1/2)x + b

Using Pt(-1,1)to solve for b

1 = -1/2 + b

b = 3/2

y = (1/2)x +3/2

The procedure for finding the inverse of a linear function is fairly basic.

1. Switch “x” and “y”.

2. Solve for “y”.

x = (1/2)y + 3/2

2x  = y + 3

2x - 3 = y   (blue line)