SOLUTION: Assume f(x) = x^2 + 1 * - What is the domain of f(x)? i put all real not equal to 0. it was wrong * - What is the range of f(x)? i put all real #'s, wrong.

Click here to see ALL problems on absolute-value

Question 356295: Assume f(x) = x^2 + 1
* - What is the domain of f(x)? i put all real not equal to 0. it was wrong
* - What is the range of f(x)? i put all real #'s, wrong.
Found 2 solutions by jim_thompson5910, edjones:
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
Since you can plug in ANY number you want for x (including zero), this means that the domain is the set of all real numbers.

It turns out that is NEVER negative. So the range of is . So just add 1 to get the range of f(x) which is

So summarize:

Domain: The set of all real numbers. Written as in interval notation.

Range: . In other words, the range is the set of numbers such that they are greater than or equal to 1. Written as [) in interval notation.

Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website!
Domain: all real numbers. It is a parabola.
Range: y when x=0 =1 so range = y[1,infinity)
Because there are no real zeros, it does not follow that the graph does not exist.
.
Ed
.