SOLUTION: I am totally lost. We just started this section last friday and he gave us an example equation but im not following. the direcions for the foirst section say that log3 7= 1.7712

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I am totally lost. We just started this section last friday and he gave us an example equation but im not following. the direcions for the foirst section say that log3 7= 1.7712       Log On


   

Question 35609: I am totally lost. We just started this section last friday and he gave us an example equation but im not following. the direcions for the foirst section say that log3 7= 1.7712 and the problem is log3 49 and i guess it would be for multiplying but otherwise i am totally clueless. i would very much appreciate help!.
-Sam
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Remember that log%28b%2CM%5EN%29+=+N%2A+log%28b%2CM%29

Therefore, log%283%2C49%29+=+log%283%2C7%5E2%29+=+2%2Alog%283%2C7%29

This means that if you know log%283%2C7%29 to find log%283%2C49%29, just multiply the value times 2.

See my Lesson Plans in algebra.com concerning logarithms, especially the ones that are indicated by "...in Living Color"!!

R^2 at SCC