SOLUTION: if you have 10 coins, comprised of nickels, dimes, and quarters, with a value of $.85, how many nickels, dimes, and quarters do you have?
.85 = .05N + .10D + .25Q
What's next
Algebra ->
Equations
-> SOLUTION: if you have 10 coins, comprised of nickels, dimes, and quarters, with a value of $.85, how many nickels, dimes, and quarters do you have?
.85 = .05N + .10D + .25Q
What's next
Log On
Question 355733: if you have 10 coins, comprised of nickels, dimes, and quarters, with a value of $.85, how many nickels, dimes, and quarters do you have?
.85 = .05N + .10D + .25Q
What's next? Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website!
Your equation is correct, but I would avoid decimals if possible.
Express everything in cents: 5N + 10D + 25Q = 85. This is your first equation. Keep in mind that there are 10 coins but we don't know how many of each kind.
So, N + D + Q = 10 is your second equation.
We now have a system of two linear equations.
