SOLUTION: Question - How do I go about solving this problem?? 3(4-6)^2-2(4-3)

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Question 3556: Question - How do I go about solving this problem??
3(4-6)^2-2(4-3)
Found 3 solutions by drglass, Pieter, JimMarshall:
Answer by drglass(89) About Me  (Show Source):
You can put this solution on YOUR website!
start by "doing the things in parentheses." %284-6%29%5E2+=+%28-2%29%5E2+=+4 and %284+-+3%29+=+1. This changes the equation to: 3(4) - 2(1) = 12 - 2 = 10

Answer by Pieter(35) About Me  (Show Source):
You can put this solution on YOUR website!
3(4-6)²-2(4-3)
=3(-2)²-2(1) (since 4-6=-2 and 4-3 = 1)
=3*4-2 (since (-2)²=(2²) because (-§)*(-§) gives §*§ = §²)
=12-2 (since 3*4 is 12)
=10
i hope you understand these things, they are the most fundamental things in math so make sure you understand them.
Greets

Answer by JimMarshall(82) About Me  (Show Source):
You can put this solution on YOUR website!
==>3(4-6)²-2(4-3)
==>3(-2)²-2(1) (since 4-6=-2 and 4-3 = 1)
==>3*4-2 (since (-2)²=(2²) because (-§)*(-§) gives §*§ = §²)
==>12-2 (since 3*4 is 12)
==>10
Ans