SOLUTION: determine the sum for the geometric sequence: n=12 , r=3 , T1 = 1/9

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Question 35496: determine the sum for the geometric sequence:
n=12 , r=3 , T1 = 1/9
Found 2 solutions by venugopalramana, Prithwis:
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
determine the sum for the geometric sequence:
n=12 , r=3 , T1 = 1/9
SN=T1(R^N-1)/(R-1)
=(1/9)(3^12-1)/(3-1)=(3^12-1)/18=29524.4

Answer by Prithwis(166) About Me  (Show Source):
You can put this solution on YOUR website!
Sum S(n) = t1(r^n-1)/(r-1) (r being the ratio and t1 being the first term)
S(12)=(1/9)(3^12-1)/(3-1)=(3^12-1)/18 (it approximates to 29524.4444)