SOLUTION: ^5sqrt(96x^5)

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Question 354941: ^5sqrt(96x^5)
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Simplifying radicals involves:
  • Eliminating any fractions within a radical
  • Eliminating any radicals in the denominator of a fraction
  • "Reducing" the radical by factoring out perfect powers of the type of root.

Since your expression (pronounced "the 5th root of 96 x to the 5th power")
root%285%2C+96x%5E5%29
has no fractions, we can skip the first two parts of simplifying. Now we just look for perfect power factors. Since your expression is a 5th root, then we look for factors which are perfect powers of 5. Obviously x%5E5 is a power of 5. But we also look for perfect powers of 5 in the 96. Since 2%5E5+=+32 and since 96 = 32*3, there is another power of 5 factor, 32, in your expression. Rewriting your expression with its radicand factored we get:
root%285%2C+32%2Ax%5E5%2A3%29
(Since multiplication is Commutative, the order of the factors is not important. I like to order the factors with the perfect power factors first and other factors, if any, at the end.)
Now we can use a basic property of all radicals, root%28a%2C+p%2Aq%29+=+root%28a%2C+p%29%2Aroot%28a%2C+q%29, to separate each factor into its own personal radical:
root%285%2C+32%29%2Aroot%285%2C+x%5E5%29%2Aroot%286%2C+3%29
The 5th roots of the power of 5 factors are easy to find:
2%2Ax%2Aroot%285%2C+3%29
or
2x%2Aroot%285%2C+3%29