SOLUTION: A binomial probability distribution has n = 15 trials with the probability of success on each trial is p = .65. Calculate the following. a. The mean, <font face = "symbol">m</fo

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Question 354696: A binomial probability distribution has n = 15 trials with the probability of success on each trial is p = .65. Calculate the following.
a. The mean, m, of the distribution
b. The standard deviation s, of the distribution
c. The probability of 10 successes
d. The probability of 10 failures
e. The probability of at least 14 successes

Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A binomial probability distribution has n = 15 trials with the probability of success on each trial is p = .65. Calculate the following.
a. The mean,, of the distribution:np
b. The standard deviation of the distribution:sqrt(npq)
c. The probability of 10 successes: binompdf(15,0.65,10)
d. The probability of 10 failures: binompdf(15,0.35,10)
e. The probability of at least 14 successes: 1 - binomcdf(15,0.65,13)
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I use a TI-84 calculator.
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cheers,
Stan H.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
A binomial probability distribution has n = 15 trials with the probability of success on each trial is p = .65.
 q=1-p=1-.65=.35, x=10

Calculate the following.

a. The mean, m, of the distribution 

mu=np=13%2A.65=1.95

b. The standard deviation s, of the distribution 

sigma=sqrt%28n%2Ap%2Aq%29=sqrt%2815%2A.65%2A.35%29=.861355921

c. The probability of (exactly) 10 successes



d. The probability of 10 failures

That's the same as exactly 5 successes. Change x to 5




e. The probability of at least 14 successes

P(14 or 15) = P(14) + P(15)





P%2814_or_15%29+=+P%2814%29+%2B+P%2815%29+=+.0126167151+%2B+.0015620695+=+.0141787846 

Edwin