SOLUTION: an expression for the product of an even integer and an odd integer is:
A) n^2
B) 4n^2 -1
C) 4n^2 + 1
D) 4n^2 +2n
E) 4n^2+4n+1
The answer is D, but I don't understand the q
Algebra ->
Problems-with-consecutive-odd-even-integers
-> SOLUTION: an expression for the product of an even integer and an odd integer is:
A) n^2
B) 4n^2 -1
C) 4n^2 + 1
D) 4n^2 +2n
E) 4n^2+4n+1
The answer is D, but I don't understand the q
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Question 354614: an expression for the product of an even integer and an odd integer is:
A) n^2
B) 4n^2 -1
C) 4n^2 + 1
D) 4n^2 +2n
E) 4n^2+4n+1
The answer is D, but I don't understand the question or how they came about the answer. Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! an expression for the product of an even integer and an odd integer is:
A) n^2
B) 4n^2 -1
C) 4n^2 + 1
D) 4n^2 +2n
E) 4n^2+4n+1
The answer is D,
---------------------
The even must be a multiple of 2: 2n
The odd must be one more than or one less then a multiple of 2:
2n+1
----
Product = 2n(2n+1) = 4n^2+2n
==============================
Cheers,
Stan H.
Every even integer can be written as 2n where n is any integer even or odd.
Every odd integer is one more than an even integer, so every odd integer can be
written as an even integer, 2n, plus 1 or 2n+1, where n is any even integer,
even or odd. (Note: 0 is considered an even integer)
So the product of an even integer and an odd integer is
2n times 2n+1 or
2n(2n+1)
or multiplying that out
4nē+2n
That's why the answer is D)
Edwin
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