SOLUTION: Mike can make 60% of his attempts from the foul line. Jake can make 70% of his attempts from the foul line.
A. If each man shoots once what is the probability that they both ma
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-> SOLUTION: Mike can make 60% of his attempts from the foul line. Jake can make 70% of his attempts from the foul line.
A. If each man shoots once what is the probability that they both ma
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Question 354607: Mike can make 60% of his attempts from the foul line. Jake can make 70% of his attempts from the foul line.
A. If each man shoots once what is the probability that they both make a basket?
B. If each man shoots once what is the probability that at least on of them will make a basket?
C. If he shoots 4 times, what is the probability that Jake makes all 4 shots
D. If he shoots 4 times what is the probabilty that mike misses all 4 shots? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Mike can make 60% of his attempts from the foul line. Jake can make 70% of his attempts from the foul line.
A. If each man shoots once what is the probability that they both make a basket?
The events are independent:
Ans: 0.6*0.7 = 0.42
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B. If each man shoots once what is the probability that at least on of them will make a basket?
Ans: (at least one make it) = 1 - P(both miss)
= 1 - 0.4*-0.3 = 1- 0.12 = 0.88
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C. If he shoots 4 times, what is the probability that Jake makes all 4 shots
Ans: 0.7^4 = 0.2401
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D. If he shoots 4 times what is the probabilty that mike misses all 4 shots?
Ans 0.4^4 = 0.0256
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Cheers,
Stan H.
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