SOLUTION: Can you help me, please? Thank you very much in advance! log(x+9) + log x = 1

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Can you help me, please? Thank you very much in advance! log(x+9) + log x = 1      Log On


   



Question 354499: Can you help me, please?
Thank you very much in advance!

log(x+9) + log x = 1

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
log%28%28x%2B9%29%29%2B+log+x+=+1,
log%28x%28x%2B9%29%29+=+1,
10%5E1+=+x%28x%2B9%29,or
x%5E2%2B9x-10=0
%28x%2B10%29%28x-1%29=0,
x+=+-10, or x+=+1.
Eliminate x+=+-10, as it is an extraneous root (won't satisfy the original equation.) Therefore the solution is x+=+1.