SOLUTION: A box contains 9 red marbles, 8 green marbles, 5 yellow marbles, and 2 blue marbles. If 3 marbles are drawn at random, without replacement, what is the probability that all 3 marbl
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-> SOLUTION: A box contains 9 red marbles, 8 green marbles, 5 yellow marbles, and 2 blue marbles. If 3 marbles are drawn at random, without replacement, what is the probability that all 3 marbl
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Question 354259: A box contains 9 red marbles, 8 green marbles, 5 yellow marbles, and 2 blue marbles. If 3 marbles are drawn at random, without replacement, what is the probability that all 3 marbles are green? Answer by ewatrrr(24785) (Show Source):
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*Note: box contains 24 marbles total. 8 of which are green.
.
First draw
P(green)= 8/24
.
second draw ( one green gone)
P(green)= = 7/23
.
third draw (two green gone)
P(green)= 6/22
.
P(All 3 draws are green) = (8/24)*(7/23)*(6/22)
