SOLUTION: How would you find the length of each leg of a right triangle if the legs are expressed as: x and another leg as: x+1. The hypotenuse is 6.

Algebra ->  Triangles -> SOLUTION: How would you find the length of each leg of a right triangle if the legs are expressed as: x and another leg as: x+1. The hypotenuse is 6.       Log On


   

Question 354240: How would you find the length of each leg of a right triangle if the legs are expressed as: x and another leg as: x+1. The hypotenuse is 6.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+(x+1)^2=6^2
x^2+x^2+2x+1=36
2x^2+2x+1-36=0
2x^2+2x-35=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(-2+-sqrt[2^2-4*2*-35])/2*2
x=(-2+-sqrt[4+280])/4
x=(-2+-sqrt284)/4
x=(-2+-16.852)/4
x=(-2+16.852)/4
x=14.852/4
x=3.713 ans.
x=(-2-16.852)/4
x=-18.852/4
x=-4.713 ans.